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MS-SQL

Group by ... Having์ ˆ

๐Ÿฉท ์Šˆ ๐Ÿงก 2014. 5. 13. 16:46
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select UserID, count(UserID) orderCnt from [์ฃผ๋ฌธํ…Œ์ด๋ธ”]
group by UserID
having COUNT(UserID) > 2

 

์ฃผ๋ฌธํ…Œ์ด๋ธ”์—์„œ ์ฃผ๋ฌธํšŸ์ˆ˜ 2ํšŒ์ด์ƒ์ธ ํšŒ์›๋งŒ ๋ฝ‘์•„๋‚ผ๋•Œ.

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